Thursday, October 10, 2013

ALGORITHM TO FIND SUM OF THE SERIES 1*5 - 2*7 + 3*9 - 4*11 ... UPTO N TERMS


STEP 1.      I <-- 1, J=5, Sum <-- 0, N <-- 0, Sign=1
STEP 2.      Read N
STEP 3.      While (I <= N)
        Begin
             Sum <-- Sum+  Sign*(I * J)
         J <-- J + 2
      I <-- I + 1
      Sign= Sign * (-1)
             End
STEP 4.      Print Sum

ALGORITHM TO FIND SUM OF THE SERIES 2+5+8+11...UPTO N TERMS


STEP 1.      I <-- 0, J=2, Sum <-- 0, N <-- 0
STEP 2.      Read N
STEP 3.      While (I <= N-1)
        Begin
             Sum <-- Sum+ J
         J <-- J + 3
      I <-- I + 1
             End
STEP 4.      Print Sum

Algorithm to print all the integers between 1 and N which are evenly divisible by 6 and 7

STEP 1.      I <-- 1, N <-- 0
STEP 2.      Read N
STEP 3.      While (I <= N) do Steps 4 and 5
STEP 4.      Is (I mod 6 = 0 AND I mod 7 = 0) Then
Begin
Print I
End
STEP 5.      I <-- I + 1

ALGORITHM TO FIND SUM OF THE SERIES 1+3+5+7+….UPTO N TERMS


STEP 1.       I <-- 0, J<--1, Sum <-- 0, N <-- 0
STEP 2.       Read N
STEP 3.       While (I <= N-1)
        Begin
             Sum <-- Sum+ J
         J <-- J + 2
      I <-- I + 1
             End
STEP 4.       Print Sum